DiffEq - Pond

1363 days ago by Carissa.Fraser

K = -ln(.65)/30 R = -ln(2)/100 P = (1/900) + ln(2)/100 Q(t) = ((.06)*e^(-K*t))/(P-K) + (4.995-(.06)/(P-K))*e^(-P*t) Q 
       
t |--> (-0.0600000000000000/(1/100*log(2) - 0.0132483194253040) +
4.99500000000000)*e^(-1/900*(9*log(2) + 1)*t) +
0.0600000000000000*e^(-0.0143594305364151*t)/(1/100*log(2) -
0.0132483194253040)
t |--> (-0.0600000000000000/(1/100*log(2) - 0.0132483194253040) + 4.99500000000000)*e^(-1/900*(9*log(2) + 1)*t) + 0.0600000000000000*e^(-0.0143594305364151*t)/(1/100*log(2) - 0.0132483194253040)
plot(Q, t, -5, 300) 
       
plot(Q, t, -5, 50) 
       
plot(Q, t, -5, 300)